Новое решение

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правка #18728 позже →
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+### Statement
+
+$14.3.15.$ [Insert the problem statement]
+
+### Solution
+
+\documentclass[12pt,a4paper]{article}
+\usepackage[english]{babel}
+\usepackage{float}
+\usepackage{wrapfig}
+\usepackage{lmodern}
+\usepackage[T1]{fontenc}
+\usepackage[utf8]{inputenc}
+\usepackage{microtype}
+\usepackage{graphicx}
+\usepackage{booktabs}
+\usepackage{amsmath,amssymb}
+\usepackage{hyperref}
+\usepackage{csquotes}
+\usepackage{geometry}
+\usepackage{subcaption}
+\usepackage{tikz}
+\usepackage{array}
+\usepackage{pgfplots}
+\usepackage{wrapfig}
+\usepackage{subcaption}
+
+\begin{document}
+$14.3.15$ How many times will the amplitude of a plane electromagnetic wave change
+when it passes into a coordinate system moving at a speed $\beta c$ in the direction
+of wave propagation?\\
+
+To solve this problem we need to use the Lorentz transformation for fields, taking into account that the fields of the electromagnetic wave are
+perpendicular to the velocity of the moving frame. Also, in each frame, the relation $\vec{E} = [\vec{v} \times \vec{B}]$ holds, where $\vec{v}$ is the
+velocity vector of the electromagnetic wave; in this case $\vec{v} = \vec{c}$.
+
+\begin{equation}
+ E' = \frac{E - \beta c B}{\sqrt{1-\beta^2}} = E \sqrt{\frac{1-\beta}{1+\beta}}
+\end{equation}
+
+And using the relation between fields:
+
+\begin{equation}
+ B' = B \sqrt{\frac{1-\beta}{1+\beta}}
+\end{equation}
+
+Thus, the amplitude becomes $\sqrt{\frac{1-\beta}{1+\beta}}$ times smaller.
+
+\end{document}
+
+#### Answer
+
+[Insert a concise answer or boxed result]