Правка разделов «Statement», «Solution», «Answer»

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@@ -1,14 +1,22 @@
### Statement
−$12.2.1.$ [Insert the problem statement]
+$12.2.1.$
+
+According to the Huygens-Fresnel principle, each section of the wave front is
+a source of a secondary spherical wave. The envelope of these waves gives a
+new wave front. Show, using this principle, that: a) the plane front of an elec-
+tromagnetic wave moves at the speed of light c in the direction perpendicular
+to the plane of the front; b) the radius of the spherical front increases by τc
+over time τ.
+
### Solution
Huygens–Fresnel Principle (recall)
At time t, the position of the wavefront is known.
Each point on that wavefront becomes a source of secondary spherical waves of radius c\tau (where \tau is the considered time interval).
−The new wavefront at time t+\tau is the envelope surface of all those secondary spheres.
+The new wavefront at time $t+\tau$ is the envelope surface of all those secondary spheres.
Note: c is the speed of light in vacuum.
@@ -22,52 +30,54 @@Solution
We apply Huygens–Fresnel:
−· Each point P(0, y, z) on the plane x = 0 emits a secondary spherical wave that reaches a radius c\tau in time \tau.
−· The spheres have centers on the plane x = 0 and all have the same radius R = c\tau.
+· Each point $P(0, y, z)$ on the plane x = 0 emits a secondary spherical wave that reaches a radius $c\tau$ in time $\tau$.
+· The spheres have centers on the plane x = 0 and all have the same radius $ R = c\tau$.
Geometry of the envelopes:
The envelope of a set of spheres of equal radius whose centers lie on a plane is another parallel plane, located at a distance equal to the radius.
−The spheres centered at (0, y, z) just touch the plane x = c\tau.
−No sphere reaches beyond x = c\tau.
−The plane x = c\tau is tangent to all spheres (because the minimum distance from any center (0, y, z) to the plane x = c\tau is exactly c\tau).
+The spheres centered at (0, y, z) just touch the plane $ x = c\tau$.
+No sphere reaches beyond $x = c\tau$.
+The plane $x = c\tau$ is tangent to all spheres (because the minimum distance from any center (0, y, z) to the plane $x = c\tau$ is exactly f c\tau)$.
Result:
−The new wavefront at time \tau is the plane x = c\tau. Therefore, in time \tau the wavefront has advanced a distance c\tau in the direction perpendicular to itself.
+The new wavefront at time $\tau $is the plane$ x = c\tau$. Therefore, in time $\tau$ the wavefront has advanced a distance $c\tau$ in the direction perpendicular to itself.
Speed:
−v = \frac{\text{displacement}}{\text{time}} = \frac{c\tau}{\tau} = c
+$v = \frac{\text{displacement}}{\text{time}} = \frac{c\tau}{\tau} = c$
−\boxed{\text{The plane wavefront moves with speed } c \text{ perpendicular to the plane.}}
+$\boxed{\text{The plane wavefront moves with speed } c \text{ perpendicular to the plane.}}$
Part b)
We apply Huygens–Fresnel:
−Each point P on the spherical surface of radius R emits a secondary spherical wave of radius c\tau after time \tau.
+Each point P on the spherical surface of radius R emits a secondary spherical wave of radius$ c\tau$ after time$ \tau$.
Geometry of the envelope:
The centers of the secondary spheres lie on the original sphere of radius R.
−All secondary spheres have the same radius c\tau.
+All secondary spheres have the same radius $c\tau$.
−The envelope of all these spheres is another sphere concentric with the original one, whose radius is R + c\tau.
+The envelope of all these spheres is another sphere concentric with the original one, whose radius is $R + c\tau$.
Justification:
−A point Q is on the outer envelope if there exists a center P on the original sphere such that Q lies on the corresponding secondary sphere and, moreover, the direction O \to P \to Q is radial. In that case:
+A point Q is on the outer envelope if there exists a center P on the original sphere such that Q lies on the corresponding secondary sphere and, moreover, the direction $O \to P \to Q$ is radial. In that case:
−OQ = OP + PQ = R + c\tau
+$OQ = OP + PQ = R + c\tau$
−Since this holds for all directions, the envelope is the sphere of radius R + c\tau.
+Since this holds for all directions, the envelope is the sphere of radius$ R + c\tau$.
−Increase in radius in time \tau:
+Increase in radius in time $\tau$:
−\Delta R = (R + c\tau) - R = c\tau
+$\Delta R = (R + c\tau) - R = c\tau$
−\boxed{\text{The radius of a spherical wavefront increases by } c\tau \text{ during a time } \tau.}
+$\boxed{\text{The radius of a spherical wavefront increases by } c\tau \text{ during a time } \tau.}$
−
#### Answer
−[Insert a concise answer or boxed result]
+$\boxed{\text{The plane wavefront moves with speed } c \text{ perpendicular to the plane.}}$
+
+
+$\boxed{\text{The radius of a spherical wavefront increases by } c\tau \text{ during a time } \tau.}$