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+### Statement
+
+$11.3.14.$ [Insert the problem statement]
+
+### Solution
+
+For two ideal inductors with self‑inductances$ L_1 $and $L_2$ and mutual inductance coefficient $M = L_{12}$, connected in series
+
+the total magnetic flux may be reinforced or partially cancelled depending on the relative orientation of the windings. The total inductance of the circuit is:
+
+$\boxed{L_{\text{total}} = L_1 + L_2 \pm 2L_{12}}$
+
+The positive sign is taken when the currents in both coils produce magnetic fields that add (series‑aiding connection, fluxes in the same direction); the negative sign corresponds to fields that oppose each other (series‑opposing connection, fluxes in opposite directions).
+
+
+#### Answer
+
+[Insert a concise answer or boxed result]