Правка разделов «Statement», «Solution»
en/12.1.32.md
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| ### Statement | |||
| − | $12.1.32.$ | ||
| + | $12.1.32.$ | ||
| + | How does the phase of a wave reflected from a plane interface between two | ||
| + | dielectrics with permittivity ε1and ε2change in the case of ε1< ε2? in the | ||
| + | case of ε1> ε2? The wave falls perpendicular to the interface plane. | ||
| ### Solution | |||
| a) Perpendicular component of the electric field | |||
| When the wave is incident on the boundary, the electric field displaces charges inside the dielectric, causing induced surface charges to accumulate at the interface. These charges generate an additional electric field that, inside the medium, is perpendicular to the surface and opposes the incident field. Consequently, only the perpendicular component of the electric field intensity $\mathbf{E}$ is reduced by a factor$ \varepsilon$. The parallel component, not being affected by these charges, does not change. | |||
| @@ -11,7 +14,3 @@Solution | |||
| b) Parallel component of the magnetic induction | |||
| The time variation of the wave's electric field produces induced surface currents at the boundary. These currents create an additional magnetic field that, inside the medium, is parallel to the surface and reinforces the magnetic field of the incident wave. Therefore, only the parallel component of the magnetic induction $\mathbf{B}$ increases by a factor $\mu$. The perpendicular component is not altered by these currents and remains unchanged. | |||
| − | |||
| − | #### Answer | ||
| − | |||
| − | [Insert a concise answer or boxed result] | ||
| @@ -1,6 +1,9 @@ | |||
| ### Statement | ### Statement | ||
| $12.1.32.$ |
$12.1.32.$ | ||
| How does the phase of a wave reflected from a plane interface between two | |||
| dielectrics with permittivity ε1and ε2change in the case of ε1< ε2? in the | |||
| case of ε1> ε2? The wave falls perpendicular to the interface plane. | |||
| ### Solution | ### Solution | ||
| a) Perpendicular component of the electric field | a) Perpendicular component of the electric field | ||
| When the wave is incident on the boundary, the electric field displaces charges inside the dielectric, causing induced surface charges to accumulate at the interface. These charges generate an additional electric field that, inside the medium, is perpendicular to the surface and opposes the incident field. Consequently, only the perpendicular component of the electric field intensity $\mathbf{E}$ is reduced by a factor$ \varepsilon$. The parallel component, not being affected by these charges, does not change. | When the wave is incident on the boundary, the electric field displaces charges inside the dielectric, causing induced surface charges to accumulate at the interface. These charges generate an additional electric field that, inside the medium, is perpendicular to the surface and opposes the incident field. Consequently, only the perpendicular component of the electric field intensity $\mathbf{E}$ is reduced by a factor$ \varepsilon$. The parallel component, not being affected by these charges, does not change. | ||
| @@ -11,7 +14,3 @@Solution | |||
| b) Parallel component of the magnetic induction | b) Parallel component of the magnetic induction | ||
| The time variation of the wave's electric field produces induced surface currents at the boundary. These currents create an additional magnetic field that, inside the medium, is parallel to the surface and reinforces the magnetic field of the incident wave. Therefore, only the parallel component of the magnetic induction $\mathbf{B}$ increases by a factor $\mu$. The perpendicular component is not altered by these currents and remains unchanged. | The time variation of the wave's electric field produces induced surface currents at the boundary. These currents create an additional magnetic field that, inside the medium, is parallel to the surface and reinforces the magnetic field of the incident wave. Therefore, only the parallel component of the magnetic induction $\mathbf{B}$ increases by a factor $\mu$. The perpendicular component is not altered by these currents and remains unchanged. | ||
| #### Answer | |||
| [Insert a concise answer or boxed result] | |||