Solution

In the GHS, the EMP law for a vortex electric field is written:

$$C_E = - \frac{1}{c} \frac{d \Phi_B}{dt}$$

The right screw, unlike the left screw, means a change of sign before the coefficient, so in the GHS the law for the vortex magnetic field looks like:

$$C_B = \frac{1}{c} \frac{d \Phi_D}{dt}$$

In GHS, we have a displacement flow equal to the field flow. To convert to SI, we will use the standard ratios:

$$B_{GHS} = B_{SI} \cdot\sqrt{\frac{4\pi}{\mu_0}}$$

$${\Phi_E}_{GHS} ={\Phi_E}_{SI} \cdot\sqrt{4\pi\varepsilon_0}$$
After substituting this into the GHS equation and replacing the electric field flux with $\frac{\Phi_D}{\varepsilon_0}$:

$$C_B = \mu_0 \frac{d \Phi_D}{dt}$$

Savchenko apparently made a typo in his answer to SI and wrote a connection with the flow of the electric field and not with the displacement flow.