Solution

By Newton's law gravitation:
$F=G\frac{m_1 m_2}{r^2}$
where $m_1$ is my mass, $m_2$ is the mass of the celestial body, and $r$ is the distance between the center of the body and me
Using $G=6.674×10^{-11}\frac{Nm^2}{kg^2}$
For me and Earth:
$m_1=70kg$
$m_{Earth}=5.972×10^{24}kg$
$r_{Earth}=6.371×10^6m$ (that's Earth's radius, assuming that I'm at sea level)
and calculating
$F_{Earth}\approx 686N$ (this is equeal to my weight!, $mg=70kg×9.8\frac{m}{s^2}$)
For me and the Moon:
$m_{Moon}=7.342×10^{22}kg$
Average Earth–Moon distance: $r=3.844×10^8m$
and calculating
$F_{Moon}\approx 2.4×10^{-3}N$
For me and the Sun:
$m_{Sun}=1.989×10^{30}kg$
Average Earth–Sun distance: $r=1.496×10^{11}m$
and calculating
$F_{Sun}\approx 0.414N$