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+ <meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
+ <meta name="description" content=""The ship was going at the limit, further acceleration was not provided for by the instructions of the space Fleet. An hour later, the speed increased by a thousand kilometers per second" (Kir Bulychev. Agent KF / / Chemistry and Life. 1984. No. 12, p. 111). Find the acceleration of the ship. How many times does it exceed the acceleration of gravity on Earth?">
+ <meta name="author" content="Aliaksandr Melnichenka">
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+ <meta property="og:title" content=""The ship was going at the limit, further acceleration was not provided for by the instructions of the space Fleet. An hour later, the speed increased by a thousand kilometers per second" (Kir Bulychev. Agent KF / / Chemistry and Life. 1984. No. 12, p. 111). Find the acceleration of the ship. How many times does it exceed the acceleration of gravity on Earth?">
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+ <title>"The ship was going at the limit, further acceleration was not provided for by the instructions of the space Fleet. An hour later, the speed increased by a thousand kilometers per second" (Kir Bulychev. Agent KF / / Chemistry and Life. 1984. No. 12, p. 111). Find the acceleration of the ship. How many times does it exceed the acceleration of gravity on Earth?</title>
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+ <h2>Solutions of Savchenko Problems in Physics</h2>
+ <p class="author">
+ Aliaksandr Melnichenka <br/>
+ October 2023
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../#1.2">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $1.2.13.$ "The ship was going at the limit, further acceleration was not provided for by the instructions of the space Fleet. An hour later, the speed increased by a thousand kilometers per second" (Kir Bulychev. Agent KF / / Chemistry and Life. 1984. No. 12, p. 111). Find the acceleration of the ship. How many times does it exceed the acceleration of gravity on Earth?
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ 1. Determine the acceleration of the ship
+$$a=\frac{\Delta v}{\Delta t}=278 \,\frac{m}{s}$$
+2. Let's relate the acceleration of the spaceplane to the acceleration of free fall on Earth
+$$\frac{a}{g}=27.8$$
+
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $28 \text{ times}$
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