Translated 1.3.3-1.3.15; Fixed GUI image generator

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+ <meta name="description" content="From the opening of the hose covered with a finger, two jets are shot at an angle \alpha and \beta to the horizon with the same initial velocity v. At what horizontal distance from the hole will the jets intersect?">
+ <meta name="author" content="Aliaksandr Melnichenka">
+ <meta name="date" content="2023-10" scheme="YYYY-MM">
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+ <title>From the opening of the hose covered with a finger, two jets are shot at an angle \alpha and \beta to the horizon with the same initial velocity v. At what horizontal distance from the hole will the jets intersect?</title>
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+ <header style="text-align:center;">
+ <h2>Solutions of Savchenko Problems in Physics</h2>
+ <p class="author">
+ Aliaksandr Melnichenka <br/>
+ October 2023
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../../#1.3">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $1.3.11.$ From the opening of the hose covered with a finger, two jets are shot at an angle $\alpha$ and $\beta$ to the horizon with the same initial velocity $v$. At what horizontal distance from the hole will the jets intersect?
+</p>
+<center>
+ <figure>
+ <img src="https://savchenkosolutions.com/1/1.3.11/statement.png"
+ loading="lazy" width="230" />
+ <figcaption>
+ For problem $1.3.11$
+ </figcaption>
+ </figure>
+</center>
+<p>
+
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+
+$$ vt_{1} \cdot \cos \alpha = vt_{2} \cdot \cos \beta $$
+
+$$ vt_{1}\cdot \sin\alpha - \frac{gt_{1}^{2}}{2}=vt_{2}\cdot \sin\beta-\frac{gt_{2}^{2}}{2} $$
+<p>From the first equation,</p>
+$$ t_{1}=t_{2} \cdot \frac{\cos \beta}{\cos \alpha} $$
+<p>We substitute $t_{1}$ into the second equation and express $t_{2}$. Trigonometric formulas 63 will come in handy. The $t_{2}$ we have already obtained is enough to insert into $x=vt_{2}cos\beta$, where $x$ is the desired distance.</p>
+<p>Using trigonometric formulas:</p>
+$$ t_{2}= \frac{2\nu ^{2}}{g(tg\beta +tg\alpha )cos\beta } $$
+
+$$ \fbox{$x = \frac{2\nu ^{2}}{g(tg\beta +tg\alpha )}$} $$
+
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $$x = \frac{2\nu ^{2}}{g(tg\beta +tg\alpha )}$$
+ </p>
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