Translated 1.3.3-1.3.15; Fixed GUI image generator

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+ <meta name="description" content="At what speed should a projectile fly out of a cannon at the moment of rocket launch in order to hit a rocket starting vertically with acceleration a? The distance from the gun to the rocket launch site is L, the gun fires at an angle of 45^\circ to the horizon.">
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+ <meta name="date" content="2023-10" scheme="YYYY-MM">
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+ <title>At what speed should a projectile fly out of a cannon at the moment of rocket launch in order to hit a rocket starting vertically with acceleration a? The distance from the gun to the rocket launch site is L, the gun fires at an angle of 45^\circ to the horizon.</title>
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+ <header style="text-align:center;">
+ <h2>Solutions of Savchenko Problems in Physics</h2>
+ <p class="author">
+ Aliaksandr Melnichenka <br/>
+ October 2023
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../../#1.3">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $1.3.9.$ At what speed should a projectile fly out of a cannon at the moment of rocket launch in order to hit a rocket starting vertically with acceleration $a$? The distance from the gun to the rocket launch site is $L$, the gun fires at an angle of $45^\circ$ to the horizon.
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ Let's use the formula for the $x$ and $y$ coordinates obtained in <a href="../1.3.6" target="_blank">1.3.6</a>:
+$$ y(t) = \frac{1}{\sqrt{2}}vt - \frac{gt^2}{2} $$
+
+$$ x(t) = \frac{1}{\sqrt{2}}vt $$
+In this case, the equation describing the rocket’s motion is:
+$$ y(t) = \frac{at^2}{2} $$
+We write down the meeting conditions:
+$$ \frac{1}{\sqrt{2}}vt - \frac{gt^2}{2} = \frac{at^2}{2}\;(1) $$
+
+$$ \frac{1}{\sqrt{2}}vt = L $$
+Where, moment of meeting:
+$$ t = \frac{\sqrt{2}L}{v} $$
+
+$$ L=\frac{v\sqrt{2}}{g} $$
+Substitute into $(1)$:
+$$ \frac{v\sqrt{2}}{g} = \frac{(a+g)v^2}{g} $$
+We obtain the required speed:
+$$ \fbox{$ v=\sqrt{L(a+g)} $} $$
+
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $$v=\sqrt{L(a+g)}$$
+ </p>
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