A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?

Solutions of Savchenko Problems in Physics

Aliaksandr Melnichenka
October 2023

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    <h3> Statement </h3>
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        $2.1.18.$ A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed $m_0$ in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to $\mu$? With what acceleration does the magnetic suspension slide, if the mass of the load is $m > m_0$?
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    <h3>Solution</h3>
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1. If a horizontal force is applied to a body, and it does not move despite efforts, then it is natural to assume that something is preventing this. And this "something" is the static friction force, equal in magnitude to the applied force. The magnitude of the static friction force can change depending on the magnitude of the applied force. The greatest value of the friction force, at which sliding does not yet occur, is determined as: $$F_{тp(max)} = \mu N = \mu mg = 51 \\,N$$ 2. The static friction force, like any decent force, has a direction, it is directed towards the possible (virtual) movement, and at zero external force, the friction force will also be zero. Thus, the static friction force changes linearly from zero to the maximum value, remaining constant thereafter. The external force begins to impart acceleration to the body.

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