| <!DOCTYPE html> | | <!DOCTYPE html> |
| <html lang="en"> | | <html lang="en"> |
| | | |
| <head> | | <head> |
| <meta charset="utf-8"> | | <meta charset="utf-8"> |
| <meta name="viewport" content="width=device-width, initial-scale=1.0"> | | <meta name="viewport" content="width=device-width, initial-scale=1.0"> |
| <meta http-equiv="content-language" content="en"> | | <meta http-equiv="content-language" content="en"> |
| <meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda"> | | <meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda"> |
| <meta name="description" content="A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?"> | | <meta name="description" content="A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?"> |
| <meta name="author" content="Aliaksandr Melnichenka"> | | <meta name="author" content="Aliaksandr Melnichenka"> |
| <meta name="date" content="2023-10" scheme="YYYY-MM"> | | <meta name="date" content="2023-10" scheme="YYYY-MM"> |
| <meta property="og:title" content="A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?"> | | <meta property="og:title" content="A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?"> |
| <meta property="og:image" content="img/logo.png"> | | <meta property="og:image" content="img/logo.png"> |
| <meta property="og:description" content="A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?"> | | <meta property="og:description" content="A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?"> |
| <meta name="yandex-verification" content="6cfda41f74038368"> | | <meta name="yandex-verification" content="6cfda41f74038368"> |
| <title>A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?</title> | | <title>A light magnet with a hook on a vertical steel plate remains stationary as long as the weight suspended from it does not exceed m_0 in mass. What is the magnetic force if the coefficient of friction of the magnet on steel is equal to \mu? With what acceleration does the magnetic suspension slide, if the mass of the load is m > m_0?</title> |
| <link rel="stylesheet" href="https://savchenkosolutions.com/css/css-latex/style.css"> | | <link rel="stylesheet" href="https://savchenkosolutions.com/css/css-latex/style.css"> |
| <link rel="icon" href="https://savchenkosolutions.com/img/logo.png" type="image/png"> | | <link rel="icon" href="https://savchenkosolutions.com/img/logo.png" type="image/png"> |
| <script src="https://savchenkosolutions.com/js/jquery-1.10.1.min.js"></script> | | <script src="https://savchenkosolutions.com/js/jquery-1.10.1.min.js"></script> |
| <script async src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.7/MathJax.js?config=TeX-MML-AM_CHTML"></script> | | <script async src="https://cdnjs.cloudflare.com/ajax/libs/mathjax/2.7.7/MathJax.js?config=TeX-MML-AM_CHTML"></script> |
| <script type="text/x-mathjax-config"> | | <script type="text/x-mathjax-config"> |
| MathJax.Hub.Config({ | | MathJax.Hub.Config({ |
| extensions: ['tex2jax.js'], | | extensions: ['tex2jax.js'], |
| jax: ['input/TeX', 'output/HTML-CSS'], | | jax: ['input/TeX', 'output/HTML-CSS'], |
| tex2jax: { | | tex2jax: { |
| inlineMath: [['$', '$'], ['$', '$']], | | inlineMath: [['$', '$'], ['$', '$']], |
| processEscapes: true, | | processEscapes: true, |
| processClass: 'tex2jax', | | processClass: 'tex2jax', |
| ignoreClass: 'html' | | ignoreClass: 'html' |
| }, | | }, |
| showProcessingMessages: false, | | showProcessingMessages: false, |
| messageStyle: 'none' | | messageStyle: 'none' |
| }); | | }); |
| </script> | | </script> |
| </head> | | </head> |
| <body style=""> | | <body style=""> |
| <header style="text-align:center;"> | | <header style="text-align:center;"> |
| <h2>Solutions of Savchenko Problems in Physics</h2> | | <h2>Solutions of Savchenko Problems in Physics</h2> |
| <p class="author"> | | <p class="author"> |
| Aliaksandr Melnichenka <br/> | | Aliaksandr Melnichenka <br/> |
| October 2023 | | October 2023 |
| </p> | | </p> |
| </header> | | </header> |
| | | |
| <h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3> | | <h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3> |
| <p> | | <p> |
| <center> | | <center> |
| <figure> | | <figure> |
| <img src="https://savchenkosolutions.com/2/2.1.18/1.png" | | <img src="https://savchenkosolutions.com/2/2.1.18/1.png" |
| loading="lazy" width="250" /> | | loading="lazy" width="250" /> |
| <figcaption> | | <figcaption> |
| Dependence of friction force on thread tension force | | Dependence of friction force on thread tension force |
| </figcaption> | | </figcaption> |
| </figure> | | </figure> |
| </center> | | </center> |
| | | |
| <p> | | <p> |
| 1. If a horizontal force is applied to a body, and it does not move despite efforts, then it is natural to assume that something is preventing this. And this "something" is the static friction force, equal in magnitude to the applied force. The magnitude of the static friction force can change depending on the magnitude of the applied force. The greatest value of the friction force, at which sliding does not yet occur, is determined as: | | 1. If a horizontal force is applied to a body, and it does not move despite efforts, then it is natural to assume that something is preventing this. And this "something" is the static friction force, equal in magnitude to the applied force. The magnitude of the static friction force can change depending on the magnitude of the applied force. The greatest value of the friction force, at which sliding does not yet occur, is determined as: |
| $$ F_{тp(max)} = \mu N = \mu mg = 51 \,N $$ | | $$ F_{тp(max)} = \mu N = \mu mg = 51 \,N $$ |
| 2. The static friction force, like any decent force, has a direction, it is directed towards the possible (virtual) movement, and at zero external force, the friction force will also be zero. Thus, the static friction force changes linearly from zero to the maximum value, remaining constant thereafter. The external force begins to impart acceleration to the body. | | 2. The static friction force, like any decent force, has a direction, it is directed towards the possible (virtual) movement, and at zero external force, the friction force will also be zero. Thus, the static friction force changes linearly from zero to the maximum value, remaining constant thereafter. The external force begins to impart acceleration to the body. |
| </p> | | </p> |
| | | |
| | | |
| <footer class="row container"> | | <footer class="row container"> |
| <br> | | <br> |
| <p> | | <p> |
| <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small> | | <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small> |
| </p> | | </p> |
| <p> | | <p> |
| <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small> | | <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small> |
| </p> | | </p> |
| </footer> | | </footer> |
| </body> | | </body> |
| | | |
| </html> | | </html> |
