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+ <meta name="description" content="A thread spanned over a block with a fixed axis is passed through a slot. At the ends of the thread are suspended loads, the mass of which is m_1 and m_2. Determine the acceleration of loads if a constant frictional force F_{tr} acts on the thread from the side of the slot when it moves.">
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+ <header style="text-align:center;">
+ <h2>Solutions of Savchenko Problems in Physics</h2>
+ <p class="author">
+ Aliaksandr Melnichenka <br/>
+ October 2023
+ </p>
+ </header>
+
+ <h3 id="back-link"><a href="../../#2.1">$\leftarrow$Back</a></h3>
+
+ <h3> Statement </h3>
+ <p>
+ $2.1.25.$ A thread spanned over a block with a fixed axis is passed through a slot. At the ends of the thread are suspended loads, the mass of which is $m_1$ and $m_2$. Determine the acceleration of loads if a constant frictional force $F_{tr}$ acts on the thread from the side of the slot when it moves.
+</p>
+<center>
+ <figure>
+ <img src="https://savchenkosolutions.com/2/2.1.25/statement.png"
+ loading="lazy" width="100" />
+ <figcaption>
+ For problem $2.1.25$
+ </figcaption>
+ </figure>
+</center>
+<p>
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ <center>
+<figure>
+<img src="https://savchenkosolutions.com/2/2.1.25/sol.jpg"
+loading="lazy" width="130" />
+<figcaption>
+Forces acting on loads
+</figcaption>
+</figure>
+</center>
+
+<p>
+1. Due to the weightlessness and non-stretchability of the thread, as well as the ideal properties of the block (no losses and low weight), the problem can be solved in the following approximation)
+$$ a_1=a_2=a $$
+
+$$ T_1=T_2=T $$
+2. The equations of motion of loads in projection onto the vertical axis in this case are written as follows:
+$$ \left\{\begin{matrix}
+ m_1a = m_2g - T \\
+ m_2a =T-m_2g-F_{fr}
+ \end{matrix}\right. $$
+3. Solving the equations together, we obtain
+$$ a=\frac{(m_1-m_2)g-F_{fr}}{m_1+m_2} $$
+4. Substituting the acceleration value into the first equation of the system allows us to determine the tension of the thread
+$$ \boxed{T=m_1\frac{2m_2g+F_{fr}}{m_1+m_2}} $$
+</p>
+ </p>
+
+ <h4>Answer</h4>
+ <p>
+ $$T=m_1\frac{2m_2g+F_{fr}}{m_1+m_2}$$
+ </p>
+
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