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<meta name="description" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
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<meta property="og:description" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<title>Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.</title>
Determine the pressure force of the logs of mass $m$ on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.
</p>
<center>
<figure>
<img src="statement.png"
loading="lazy" alt="4.2.14" width="300" />
<figcaption>
For problem 4.2.14
</figcaption>
</figure>
</center>
<h3>Solution</h3>
<p>
Let's consider the following figure
</p>
<center>
<figure>
<img src="draw.png"
loading="lazy" alt="4.2.14" width="550" />
<figcaption>
Force analysis
</figcaption>
</figure>
</center>
<p>
From right figure
$$\cos{\theta} = \frac{R}{2R} = 0.5$$
so, $\theta = 60^\circ$. Applying Newton Second Law for submerged trunk on $x$-axis,
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
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<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="description" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<meta name="description" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<meta property="og:title" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<meta property="og:title" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<meta property="og:image" content="img/logo.png">
<meta property="og:image" content="img/logo.png">
@@ -14,9 +14,9 @@
<meta property="og:description" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<meta property="og:description" content="Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.">
<title>Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.</title>
<title>Determine the pressure force of the logs of mass m on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.</title>
Determine the pressure force of the logs of mass $m$ on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.
Determine the pressure force of the logs of mass $m$ on the walls of the channel. The upper log is half submerged in water, and the lower log touches the upper part of the water surface. The logs are equal.
</p>
</p>
<center>
<center>
<figure>
<figure>
<img src="statement.png"
<img src="statement.png"
loading="lazy" alt="4.2.14" width="300" />
loading="lazy" alt="4.2.14" width="300" />
<figcaption>
<figcaption>
For problem 4.2.14
For problem 4.2.14
</figcaption>
</figcaption>
</figure>
</figure>
</center>
</center>
<h3>Solution</h3>
<h3>Solution</h3>
<p>
<p>
Let's consider the following figure
Let's consider the following figure
</p>
</p>
<center>
<center>
<figure>
<figure>
<img src="draw.png"
<img src="draw.png"
loading="lazy" alt="4.2.14" width="550" />
loading="lazy" alt="4.2.14" width="550" />
<figcaption>
<figcaption>
Force analysis
Force analysis
</figcaption>
</figcaption>
</figure>
</figure>
</center>
</center>
<p>
<p>
From right figure
From right figure
$$\cos{\theta} = \frac{R}{2R} = 0.5$$
$$\cos{\theta} = \frac{R}{2R} = 0.5$$
so, $\theta = 60^\circ$. Applying Newton Second Law for submerged trunk on $x$-axis,
so, $\theta = 60^\circ$. Applying Newton Second Law for submerged trunk on $x$-axis,
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>