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<meta property="og:description" content="A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?">
<title>A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?</title>
$1.2.12.$ A boy inflates a balloon. With a ball radius of $10$ cm, the rate of increase in the radius is $1$$\frac{mm}{s}$. How much air does the boy exhale every second?
</p>
<h3>Solution</h3>
<p>
The volume of the ball is defined by the expression
$$V = \frac{4}{3}\pi r^3$$
Then, the rate of change of the hugram or the volume of air that the boy exhales every second:
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
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<meta name="description" content="A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?">
<meta name="description" content="A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?">
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<meta property="og:description" content="A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?">
<meta property="og:description" content="A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?">
<title>A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?</title>
<title>A boy inflates a balloon. With a ball radius of 10 cm, the rate of increase in the radius is 1 \frac{mm}{s}. How much air does the boy exhale every second?</title>
$1.2.12.$ A boy inflates a balloon. With a ball radius of $10$ cm, the rate of increase in the radius is $1$$\frac{mm}{s}$. How much air does the boy exhale every second?
$1.2.12.$ A boy inflates a balloon. With a ball radius of $10$ cm, the rate of increase in the radius is $1$$\frac{mm}{s}$. How much air does the boy exhale every second?
</p>
</p>
<h3>Solution</h3>
<h3>Solution</h3>
<p>
<p>
The volume of the ball is defined by the expression
The volume of the ball is defined by the expression
$$V = \frac{4}{3}\pi r^3$$
$$V = \frac{4}{3}\pi r^3$$
Then, the rate of change of the hugram or the volume of air that the boy exhales every second:
Then, the rate of change of the hugram or the volume of air that the boy exhales every second:
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
