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+ <meta name="description" content="A weight is oscillating vertically on a rubber cord. How many times will the period of vertical oscillations of the weight change if it is suspended on the same cord folded in half?">
+ <meta name="author" content="Aliaksandr Melnichenka">
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+ <span><img src = "../../img/book.png"><span><span>Savchenko Solutions</span>
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+ Solutions&nbsp;of&nbsp;Savchenko Problems&nbsp;in&nbsp;Physics <br>
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+ <h3 id="back-link"><a href="../../#3.2">$\leftarrow$Back</a></h3>
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+ <h3> Statement </h3>
+ <p>
+ $3.2.3.$ A weight is oscillating vertically on a rubber cord. How many times will the period of vertical oscillations of the weight change if it is suspended on the same cord folded in half?
+ </p>
+
+ <h3>Solution</h3>
+ <p>
+ We find the period of oscillations on a standard cord as the period of oscillations of a spring pendulum
+$$ T_1=2\pi\sqrt{\frac{m}{k}} $$
+When we fold the cord, we change its length and width and, accordingly, its stiffness $k'$ changes
+$$ T_2=2\pi\sqrt{\frac{m}{k'}} $$
+Since the spring is divided into two and the length of each half is $l/2$ and the stiffness of each of them is $k_1=2k$; by adding the two halves in parallel we obtain a parallel connection
+$$ k'=2k_1=4k $$
+We substitute the oscillation period of the “new” cord into the expression for $T_2$
+$$ T_2=2\pi\sqrt{\frac{m}{4k}}=\pi\sqrt{\frac{m}{k}} $$
+From where we obtain the ratio of the periods of oscillations
+$$ \boxed{\frac{T_1}{T_2}=2} $$
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+ <p style="text-align: right; font-style: italic; font-size: 14;">
+ Dzikan Mikita<br>
+ Aliaksandr Kanashenka
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+ <h4>Answer</h4>
+ <p>
+ The period will be halved
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