Updated greek laters @ latex compiling

astrosander edited
revision #10127 parent #9647 GitHub dbb31ba ← older newer →
@@ -79,13 +79,13 @@
$$T_2 = \pi \sqrt{\frac{l}{2g}}$$
Таким образом полный период колебаний
$$T = T_1+T_2$$
− $$\boxed{T = (1 + 1/ \sqrt{2} )π \sqrt {\frac{l}{g}}}$$
+ $$\boxed{T = (1 + 1/ \sqrt{2} )\pi \sqrt {\frac{l}{g}}}$$
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Ответ:
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− <p>$$T = (1 + 1/ \sqrt{2} )π \sqrt {\frac{l}{g}}$$</p>
+ <p>$$T = (1 + 1/ \sqrt{2} )\pi \sqrt {\frac{l}{g}}$$</p>
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