Updated spacing between @ latex expressions

astrosander edited
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revision #10492 parent #9131 GitHub c702ebe ← older newer →
en/1.2.21.md +4 −4
@@ -56,12 +56,12 @@
<h3>Solution</h3>
<p>
− $$l=\nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$
+ $$l=\nu_{1}t_{1} +\frac{at_{1}^{2}}{2}$$
−$$l=(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2}$$
+$$l=(\nu_{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2}$$
−$$(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2} = \nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$
−Given that $\nu _{1} = a{d}t$:
+$$(\nu_{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2} = \nu_{1}t_{1} +\frac{at_{1}^{2}}{2}$$
+Given that $\nu_{1} = a{d}t$:
$$a{d}t(t_{1}-t_{2}) =\frac{a(t_{2}-2t_{1}t_{2}-t_{1}^{2})}{2}$$
$${d}t=\fbox{$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$}$$
<p style="text-align: right; font-style: italic; font-size: 14;">
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