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		@@ -39,8 +39,8 @@
			<span><img src = "../../img/book.png"><span><span>Savchenko Solutions</span>
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			<p class="author">
		−	Solutions of Savchenko Problems in Physics <br/>
		−	knowledge must be free
		+	Solutions of Savchenko Problems in Physics <br>
		+	<i><b>knowledge must be free</b></i>
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			<h3 id="back-link"><a href="../../#1.2">$\leftarrow$Back</a></h3>

			<h3> Statement </h3>
			<p>
			$1.2.21^*.$ The scheduled departure time of the train is $12.00$. It's $12.00$ on your watch, but the penultimate car that moves past you during time $t_1$ is already starting to pass by you.
			The last car passes you during $t_2$. The train left on time and is moving equidistant. How far behind is your watch?
			</p>

			<h3>Solution</h3>
			<p>
			$$l=\nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$

			$$l=(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2}$$

			$$(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2} = \nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$
			Given that $\nu _{1} = a{d}t$:
			$$a{d}t(t_{1}-t_{2}) =\frac{a(t_{2}-2t_{1}t_{2}-t_{1}^{2})}{2}$$
			$${d}t=\fbox{$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$}$$
			<p style="text-align: right; font-style: italic; font-size: 14;">
			<a href="https://www.instagram.com/_den.di__/" target="_blank">Dzikan Danila</a></b>
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			<h4>Answer</h4>
			<p>
			$$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$$
			</p>


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	<span><img src = "../../img/book.png"><span><span>Savchenko Solutions</span>		<span><img src = "../../img/book.png"><span><span>Savchenko Solutions</span>
	</div>		</div>
	<p class="author">		<p class="author">
	Solutions of Savchenko Problems in Physics <br/>		Solutions of Savchenko Problems in Physics <br>
	knowledge must be free		<i><b>knowledge must be free</b></i>
	</p>		</p>
	</header>		</header>

	<h3 id="back-link"><a href="../../#1.2">$\leftarrow$Back</a></h3>		<h3 id="back-link"><a href="../../#1.2">$\leftarrow$Back</a></h3>

	<h3> Statement </h3>		<h3> Statement </h3>
	<p>		<p>
	$1.2.21^*.$ The scheduled departure time of the train is $12.00$. It's $12.00$ on your watch, but the penultimate car that moves past you during time $t_1$ is already starting to pass by you.		$1.2.21^*.$ The scheduled departure time of the train is $12.00$. It's $12.00$ on your watch, but the penultimate car that moves past you during time $t_1$ is already starting to pass by you.
	The last car passes you during $t_2$. The train left on time and is moving equidistant. How far behind is your watch?		The last car passes you during $t_2$. The train left on time and is moving equidistant. How far behind is your watch?
	</p>		</p>

	<h3>Solution</h3>		<h3>Solution</h3>
	<p>		<p>
	$$l=\nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$		$$l=\nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$

	$$l=(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2}$$		$$l=(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2}$$

	$$(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2} = \nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$		$$(\nu _{1}+at_{1})t_{2} +\frac{at_{1}^{2}}{2} = \nu _{1}t_{1} +\frac{at_{1}^{2}}{2}$$
	Given that $\nu _{1} = a{d}t$:		Given that $\nu _{1} = a{d}t$:
	$$a{d}t(t_{1}-t_{2}) =\frac{a(t_{2}-2t_{1}t_{2}-t_{1}^{2})}{2}$$		$$a{d}t(t_{1}-t_{2}) =\frac{a(t_{2}-2t_{1}t_{2}-t_{1}^{2})}{2}$$
	$${d}t=\fbox{$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$}$$		$${d}t=\fbox{$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$}$$
	<p style="text-align: right; font-style: italic; font-size: 14;">		<p style="text-align: right; font-style: italic; font-size: 14;">
	<a href="https://www.instagram.com/_den.di__/" target="_blank">Dzikan Danila</a></b>		<a href="https://www.instagram.com/_den.di__/" target="_blank">Dzikan Danila</a></b>
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	</p>		</p>

	<h4>Answer</h4>		<h4>Answer</h4>
	<p>		<p>
	$$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$$		$$\frac{t_{2}-2t_{1}t_{2}-t_{1}^{2}}{2(t_{1}-t_{2})}$$
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