Updated spacing between @ latex expressions

astrosander edited
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revision #10593 parent #9927 GitHub c702ebe ← older newer →
en/1.1.9.md +4 −4
@@ -82,7 +82,7 @@
1. The configuration of the region occupied by the products of the explosion until the moment of complete oxidation of the rod, at $\tau < L/v$ will have the form of a cone of height $h = vt$, the base of which is a hemisphere of radius $R = u \cdot t$.
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<p>
− 2. After the rod oxidation is over, i.e. for time $\tau \geq L/v$, the product region will be bounded by two hemispheres with radii
+ 2. After the rod oxidation is over, i.e. for time $\tau\geq L/v$, the product region will be bounded by two hemispheres with radii
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<p style="text-align: center;">
$$R=ut \text{ и }r=u(t-\frac{L}{v})$$
@@ -103,13 +103,13 @@
1. If the length of the cone's trunk is $L$, then its height $h$ is determined by Eq.
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<p style="text-align: center;">
− $$h = L \cdot \cos \alpha$$
+ $$h = L \cdot \cos\alpha$$
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<p>
from where
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<p style="text-align: center;">
− $$L = \frac{h}{\cos \alpha}$$
+ $$L = \frac{h}{\cos\alpha}$$
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<p>
2. According to the problem condition $t_1=t_2$, i.e.
@@ -121,7 +121,7 @@
from where
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<p style="text-align: center;">
− $$\frac{{L}}{{v}}=\frac{{L}\cos\alpha}{{u}}\quad\Rightarrow\quad\fbox{$\cos\alpha=\frac{{u}}{{v}}$}\quad$$
+ $$\frac{{L}}{{v}}=\frac{{L}\cos\alpha}{{u}}\quad\Rightarrow\quad\fbox{$\cos\alpha =\frac{{u}}{{v}}$}\quad$$
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