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			<h3 id="back-link"><a href="../../#1.1">$\leftarrow$Back</a></h3>

			<h3> Statement </h3>
			<p>
			$1.1.9.$ a. A rod of length $l$ is made of explosive material. The detonation velocity (the rate of involvement in the explosion of new parts of the explosive) is equal to $v$, and the rate of spreading of the products of the explosion is $u < v$. How does the region occupied by the products of the explosion change with time if the rod is detonated at one end? Make a drawing.
			</p>
			<p>

			b. From the same explosive material it is necessary to make such a thin-walled conical shell so that when detonating it from the top, the products of the explosion simultaneously hit the rod on the axis of the cone. What angle between the axis of the cone and the generatrix should be chosen?
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			<figcaption>
			For problem 1.1.9
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			<h3>Solution</h3>
			<p>
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			<figure>
			<img src="solution.png" alt="1.1.9"
			loading="lazy" width="300" />
			<figcaption>
			Figure to part a)
			</figcaption>
			</figure>
			</center>

			<p>
			1. The configuration of the region occupied by the products of the explosion until the moment of complete oxidation of the rod, at $\tau < L/v$ will have the form of a cone of height $h = vt$, the base of which is a hemisphere of radius $R = u \cdot t$.
			</p>
			<p>
			2. After the rod oxidation is over, i.e. for time $\tau \geq L/v$, the product region will be bounded by two hemispheres with radii
			</p>
			<p style="text-align: center;">
			$$R=ut \text{ и }r=u(t-\frac{L}{v})$$
			</p>
			<br>

			<center>
			<figure>
			<img src="1.1.9(b).png" alt="1.1.9"
			loading="lazy" width="250" />
			<figcaption>
			Figure to part b)
			</figcaption>
			</figure>
			</center>

			<p>
		@@ -103,13 +103,13 @@
			1. If the length of the cone's trunk is $L$, then its height $h$ is determined by Eq.
			</p>
			<p style="text-align: center;">
		−	$$h = L \cdot cos \alpha$$
		+	$$h = L \cdot \cos \alpha$$
			</p>
			<p>
			from where
			</p>
			<p style="text-align: center;">
		−	$$L = \frac{h}{cos \alpha}$$
		+	$$L = \frac{h}{\cos \alpha}$$
			</p>
			<p>
			2. According to the problem condition $t_1=t_2$, i.e.
			</p>
			<p style="text-align: center;">
			$${t_{1}=\frac{h}{u}=\frac{L\cos\alpha}{u};\quad t_{2}=\frac{L}{v},}$$
			</p>
			<p>
			from where
			</p>
			<p style="text-align: center;">
			$$\frac{{L}}{{v}}=\frac{{L}\cos\alpha}{{u}}\quad\Rightarrow\quad\fbox{$\cos\alpha=\frac{{u}}{{v}}$}\quad$$
			</p>
			</p>

			<h4>Answer</h4>
			<p>
			$a$. At $t < l/v$, the boundary of the region is a cone with the apex located at a distance $vt$
		@@ -131,7 +131,7 @@
			from the end of the rod, passing into a sphere of radius $ut$ touching it. At $t > l/v$, the spheres are spheres
			with centres at the ends of the rod and radii $ut$ and $u(t - l/v)$ with a conical surface tangent to them.
			tangent to them.<br>
		−	$\\ b^{∗}. \; \cos α = u/v$
		+	$\\ b^{∗}. \; \cos\alpha = u/v$
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	<h3 id="back-link"><a href="../../#1.1">$\leftarrow$Back</a></h3>		<h3 id="back-link"><a href="../../#1.1">$\leftarrow$Back</a></h3>

	<h3> Statement </h3>		<h3> Statement </h3>
	<p>		<p>
	$1.1.9.$ a. A rod of length $l$ is made of explosive material. The detonation velocity (the rate of involvement in the explosion of new parts of the explosive) is equal to $v$, and the rate of spreading of the products of the explosion is $u < v$. How does the region occupied by the products of the explosion change with time if the rod is detonated at one end? Make a drawing.		$1.1.9.$ a. A rod of length $l$ is made of explosive material. The detonation velocity (the rate of involvement in the explosion of new parts of the explosive) is equal to $v$, and the rate of spreading of the products of the explosion is $u < v$. How does the region occupied by the products of the explosion change with time if the rod is detonated at one end? Make a drawing.
	</p>		</p>
	<p>		<p>

	b. From the same explosive material it is necessary to make such a thin-walled conical shell so that when detonating it from the top, the products of the explosion simultaneously hit the rod on the axis of the cone. What angle between the axis of the cone and the generatrix should be chosen?		b. From the same explosive material it is necessary to make such a thin-walled conical shell so that when detonating it from the top, the products of the explosion simultaneously hit the rod on the axis of the cone. What angle between the axis of the cone and the generatrix should be chosen?
	<center>		<center>
	<figure>		<figure>
	<img src="statement.png"		<img src="statement.png"
	loading="lazy" width="230" />		loading="lazy" width="230" />
	<figcaption>		<figcaption>
	For problem 1.1.9		For problem 1.1.9
	</figcaption>		</figcaption>
	</figure>		</figure>
	</center>		</center>
	</p>		</p>

	<h3>Solution</h3>		<h3>Solution</h3>
	<p>		<p>
	<center>		<center>
	<figure>		<figure>
	<img src="solution.png" alt="1.1.9"		<img src="solution.png" alt="1.1.9"
	loading="lazy" width="300" />		loading="lazy" width="300" />
	<figcaption>		<figcaption>
	Figure to part a)		Figure to part a)
	</figcaption>		</figcaption>
	</figure>		</figure>
	</center>		</center>

	<p>		<p>
	1. The configuration of the region occupied by the products of the explosion until the moment of complete oxidation of the rod, at $\tau < L/v$ will have the form of a cone of height $h = vt$, the base of which is a hemisphere of radius $R = u \cdot t$.		1. The configuration of the region occupied by the products of the explosion until the moment of complete oxidation of the rod, at $\tau < L/v$ will have the form of a cone of height $h = vt$, the base of which is a hemisphere of radius $R = u \cdot t$.
	</p>		</p>
	<p>		<p>
	2. After the rod oxidation is over, i.e. for time $\tau \geq L/v$, the product region will be bounded by two hemispheres with radii		2. After the rod oxidation is over, i.e. for time $\tau \geq L/v$, the product region will be bounded by two hemispheres with radii
	</p>		</p>
	<p style="text-align: center;">		<p style="text-align: center;">
	$$R=ut \text{ и }r=u(t-\frac{L}{v})$$		$$R=ut \text{ и }r=u(t-\frac{L}{v})$$
	</p>		</p>
	<br>		<br>

	<center>		<center>
	<figure>		<figure>
	<img src="1.1.9(b).png" alt="1.1.9"		<img src="1.1.9(b).png" alt="1.1.9"
	loading="lazy" width="250" />		loading="lazy" width="250" />
	<figcaption>		<figcaption>
	Figure to part b)		Figure to part b)
	</figcaption>		</figcaption>
	</figure>		</figure>
	</center>		</center>

	<p>		<p>
	@@ -103,13 +103,13 @@
	1. If the length of the cone's trunk is $L$, then its height $h$ is determined by Eq.		1. If the length of the cone's trunk is $L$, then its height $h$ is determined by Eq.
	</p>		</p>
	<p style="text-align: center;">		<p style="text-align: center;">
	$$h = L \cdot cos \alpha$$		$$h = L \cdot \cos \alpha$$
	</p>		</p>
	<p>		<p>
	from where		from where
	</p>		</p>
	<p style="text-align: center;">		<p style="text-align: center;">
	$$L = \frac{h}{cos \alpha}$$		$$L = \frac{h}{\cos \alpha}$$
	</p>		</p>
	<p>		<p>
	2. According to the problem condition $t_1=t_2$, i.e.		2. According to the problem condition $t_1=t_2$, i.e.
	</p>		</p>
	<p style="text-align: center;">		<p style="text-align: center;">
	$${t_{1}=\frac{h}{u}=\frac{L\cos\alpha}{u};\quad t_{2}=\frac{L}{v},}$$		$${t_{1}=\frac{h}{u}=\frac{L\cos\alpha}{u};\quad t_{2}=\frac{L}{v},}$$
	</p>		</p>
	<p>		<p>
	from where		from where
	</p>		</p>
	<p style="text-align: center;">		<p style="text-align: center;">
	$$\frac{{L}}{{v}}=\frac{{L}\cos\alpha}{{u}}\quad\Rightarrow\quad\fbox{$\cos\alpha=\frac{{u}}{{v}}$}\quad$$		$$\frac{{L}}{{v}}=\frac{{L}\cos\alpha}{{u}}\quad\Rightarrow\quad\fbox{$\cos\alpha=\frac{{u}}{{v}}$}\quad$$
	</p>		</p>
	</p>		</p>

	<h4>Answer</h4>		<h4>Answer</h4>
	<p>		<p>
	$a$. At $t < l/v$, the boundary of the region is a cone with the apex located at a distance $vt$		$a$. At $t < l/v$, the boundary of the region is a cone with the apex located at a distance $vt$
	@@ -131,7 +131,7 @@
	from the end of the rod, passing into a sphere of radius $ut$ touching it. At $t > l/v$, the spheres are spheres		from the end of the rod, passing into a sphere of radius $ut$ touching it. At $t > l/v$, the spheres are spheres
	with centres at the ends of the rod and radii $ut$ and $u(t - l/v)$ with a conical surface tangent to them.		with centres at the ends of the rod and radii $ut$ and $u(t - l/v)$ with a conical surface tangent to them.
	tangent to them.<br>		tangent to them.<br>
	$\\ b^{∗}. \; \cos α = u/v$		$\\ b^{∗}. \; \cos\alpha = u/v$
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