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+### Statement
+
+$3.5.15.$ [Insert problem description here]
+
+__Example Statement__:
+$1.1.1.$ Determine the coordinate $x(t)$ of a body as a function of time $t$, given that its acceleration is defined as $a(t) = bt$, where $b$ is a constant.
+
+
+### Solution
+
+[Your solution should be placed here]
+
+__Example Solution__:
+The acceleration of the body defined by
+
+$$a(t) = bt$$
+
+We know that acceleration is the time derivative of velocity:
+
+$$a(t) = \frac{d v(t)}{d t}$$
+
+To find the velocity $v(t)$, we integrate $a(t)$ with respect to time:
+
+$$v(t) = \int a(t) \, dt = \int b t \, dt$$
+
+If the initial velocity is $v(0) = 0$, then the velocity becomes:
+
+$$v(t) = \frac{b t^2}{2}$$
+
+Likewise, integrate $v(t)$ with respect to time:
+
+$$x(t)= \int v(t) \, dt = \frac{b}{2} \int t^2 \, dt$$
+
+From where the coordinate from time, considering the initial conditions:
+
+$$\boxed{x(t)=\frac{bt^3}{6}}$$
+
+#### Answer
+
+[Insert a concise answer or boxed result, like this:]
+
+
+__Example Answer__:
+$$ x(t)=\frac{bt^3}{6} $$