Added alternative solution to 3.2.3 3.2.4 3.2.6 3.2.7 3.2.8 3.2.9 3.2.10 3.2.11 3.2.12 3.2.13 3.2.14 3.2.18 3.2.19 3.2.20 3.2.21 3.2.22 3.2.23 3.2.24 3.2.25 3.2.28 3.2.29 3.2.31

astrosander edited
revision #409 parent #366 GitHub fbdf260 ← older newer →
@@ -180,6 +180,14 @@
$R^2(M+m)\ddot{\varphi}+mgRsin\varphi=0$<br><br>
$\ddot{\varphi}+\frac{mg}{R(M+m)}\varphi=0$<br><br>
$\omega^2=\frac{mg}{R(M+m)}\Rightarrow M=m(\frac{g}{\omega^2R}-1)$<br><br>
+
+ <hr>
+ <h3>
+ Альтернативное решение:
+ </h3>
+ <div class="solutions">
+ <img class="ScreenS" src="01.jpg">
+ </div>
<h3>
Ответ: $M=m(\frac{g}{\omega^2R}-1)$.
<h3>
unchanged lines 55