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<meta name="description" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<meta property="og:title" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
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@@ -14,9 +14,9 @@
<meta property="og:description" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<title>Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.</title>
$1.1.14.$ Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is $v$, the speed of the second particle is $v/2$. The first particle at time $t = 0$ had coordinate $x = 0$, the second particle at time $t_1$ had coordinate $x = a$.
The ordinate and abscissa of the point of intersection of the graphs $x_{1} = vt$ and $x_{2} = a + v(t - t_{1})/2$ give the time and coordinate of the point of impact of the particles: $t_2 = (2a - vt_{1})/v, \, {x}' = 2a - vt_{1}$
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="keywords" content="Savchenko Problems in Physics, Savchenko solutions, physics problems, physics olympiad preparation, IPhO, Jaan Kalda">
<meta name="description" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<meta name="description" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<meta property="og:title" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<meta property="og:title" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<meta property="og:image" content="img/logo.png">
<meta property="og:image" content="img/logo.png">
@@ -14,9 +14,9 @@
<meta property="og:description" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<meta property="og:description" content="Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.">
<title>Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.</title>
<title>Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is v, the speed of the second particle is v/2. The first particle at time t = 0 had coordinate x = 0, the second particle at time t_1 had coordinate x = a.</title>
$1.1.14.$ Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is $v$, the speed of the second particle is $v/2$. The first particle at time $t = 0$ had coordinate $x = 0$, the second particle at time $t_1$ had coordinate $x = a$.
$1.1.14.$ Using coordinate-time graphs, find the point in time and place of collision of particles moving along one straight line. The speed of the first particle is $v$, the speed of the second particle is $v/2$. The first particle at time $t = 0$ had coordinate $x = 0$, the second particle at time $t_1$ had coordinate $x = a$.
The ordinate and abscissa of the point of intersection of the graphs $x_{1} = vt$ and $x_{2} = a + v(t - t_{1})/2$ give the time and coordinate of the point of impact of the particles: $t_2 = (2a - vt_{1})/v, \, {x}' = 2a - vt_{1}$
The ordinate and abscissa of the point of intersection of the graphs $x_{1} = vt$ and $x_{2} = a + v(t - t_{1})/2$ give the time and coordinate of the point of impact of the particles: $t_2 = (2a - vt_{1})/v, \, {x}' = 2a - vt_{1}$
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
<small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small>
