Making inseparable words in the heading @ GUI

astrosander edited
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revision #8807 parent #8792 GitHub df9e794 ← older newer →
en/2.7.44.md +9 −8
@@ -39,7 +39,7 @@
<span><img src = "../../img/book.png"><span><span>Savchenko Solutions</span>
</div>
<p class="author">
− Solutions of Savchenko Problems in Physics <br>
+ Solutions&nbsp;of&nbsp;Savchenko Problems&nbsp;in&nbsp;Physics <br>
<i><b>knowledge must be free</b></i>
</p>
</header>
@@ -59,8 +59,6 @@
</figcaption>
</figure>
</center>
−<p>
− </p>
<h3>Solution</h3>
<p>
@@ -83,18 +81,21 @@
$$\tau_0=\tau_f=Fx=J\varepsilon$$
From where
$$\varepsilon = \frac{Fx}{J}$$
−Newton's second law for the rotational motion
−$$F+F_0=m\varepsilon R$$
−$$F_0=mR\cdot \frac{Fx}{J}-F\Leftrightarrow \boxed{F_0=F\left(\frac{mRx}{J}-1\right)}$$
+Newton's second law
+$$F-F_0=m\varepsilon R$$
+$$F_0=F-mR\cdot \frac{Fx}{J}\Leftrightarrow \boxed{F_0=F\left(1-\frac{mRx}{J}\right)}$$
From here, the minimum values of $F_0 = 0$, described by the expression
−$$F_0=0\Leftrightarrow \frac{mRx}{J}-1=0$$
+$$F_0=0\Leftrightarrow 1-\frac{mRx}{J}=0$$
which will be observed at length that connects the point of application of the force and the axis
$$\boxed{x=\frac{J}{mR}}$$
</p>
<h4>Answer</h4>
<p>
− $F'=F(mRx/J-1)$. With $x=J/(mR),~F'=0$
+ $F'=F(1-mRx/J)$. With $x=J/(mR),~F'=0$
+ </p>
+ <p style="text-align: right; font-style: italic; font-size: 14;">
+ Almaskhan Arsen<br>
</p>
unchanged lines 12