Translated 3.2.1-3.2.17

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+ <h3> Statement </h3>
+ <p>
+ $3.2.16.$ A heavy cart rolls with acceleration $a$ on an inclined plane forming an angle $\alpha$ with the horizon. Find the period of oscillation of a pendulum of length $l$ mounted on the cart.
+</p>
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+ <figcaption>
+ For problem $3.2.16$
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+ <h3>Solution</h3>
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+ Acceleration vector $\vec{g}^*$ in an inertial frame of reference
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+<p>
+The period of oscillation of a pendulum on an inclined cart can be found using the well-known formula for the period of oscillation of a mathematical pendulum, by switching to the inertial frame of reference of the cart
+$$ T=2\pi\sqrt{\frac{l}{g^*}}\quad(1) $$
+Where $\vec{g}^*$ is the acceleration of the inertial reference frame
+$$ \vec{g}^*=\vec{g}-\vec{a} $$
+Using the cosine law, we find the value of the modulus of the vector $\vec{g}^*$
+$$ (g^{*})^2=a^2+g^2-2agcos\alpha $$
+Where
+$$ \boxed{g^*=\sqrt{a^2+g^2-2agcos\alpha}} $$
+We substitute $(1)$ into the expression and find the period of oscillation of the pendulum
+$$ \boxed{T=2\pi\sqrt{\frac{l}{\sqrt{a^2+g^2-2agcos\alpha}}}} $$
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+ <p style="text-align: right; font-style: italic; font-size: 14;">
+ Dzikan Mikita<br>
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+ <h4>Answer</h4>
+ <p>
+ $$T=2\pi\sqrt{l/{\sqrt{a^2+g^2-2agcos\alpha}}}$$
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