Усл
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<source srcset="../../img/2.4.22/Screenshot 2023-08-25 at 23.09.34.webp" type="image/webp">
<img src="/img/2.4.22/Screenshot%202023-08-25%20at%2023.09.34.png"
loading="lazy" alt="К задаче $2.4.22$"
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<figcaption>К задаче $2.4.22$</figcaption>
</figure>овие<figure class="ss-image">
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<source srcset="../../img/2.4.22/Screenshot 2023-08-25 at 23.09.34.webp" type="image/webp">
<img src="/img/2.4.22/Screenshot%202023-08-25%20at%2023.09.34.png"
loading="lazy" alt="Screenshot 2023-08-25 at 23.09.34.png"
width="400" height="242"
style="width: min(400px, 100%); height: auto;" />
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<figcaption>Screenshot 2023-08-25 at 23.09.34.png</figcaption>
</figure>; height: auto;" />
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<figcaption>scan-1.png</figcaption>
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Ответ
x = µmgcosα/k при µ ⩽ tgα; x = µmgcosα
1 +
2k
q
1 −2(1−tgα/µ)2 при
tg α ⩽ µ⩽3tgα; x=2mgsinα/k при µ⩾3tgα.