Updated greek laters @ latex compiling

astrosander edited
revision #10126 parent #9649 GitHub dbb31ba ← older newer →
@@ -81,13 +81,13 @@
$$T_2 = \pi\sqrt{\frac{r}{g}}$$
Таким образом полный период колебаний
$$T = T_1+T_2$$
− $$\boxed{T = π(\sqrt{\frac{R}{g}}+\sqrt{\frac{r}{g}})}$$
+ $$\boxed{T = \pi (\sqrt{\frac{R}{g}}+\sqrt{\frac{r}{g}})}$$
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Ответ:
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− <p>$$T = π(\sqrt{\frac{R}{g}}+\sqrt{\frac{r}{g}})$$</p>
+ <p>$$T = \pi (\sqrt{\frac{R}{g}}+\sqrt{\frac{r}{g}})$$</p>
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unchanged lines 11