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<p class="TxtSolutions">
−$N=mgcos\varphi\approx mg(1-\frac{\varphi^2}{2})=mg(1-\frac{A^2}{2R^2})$ (1)<br><br>
−$N+\Delta=m(a+g)=m(\frac{\upsilon^2}{R}+g)$<br><br>
−$mgR(1-cos\varphi)\approx mgR\frac{\varphi^2}{2}=\frac{m\upsilon^2}{2}$ - ЗСЭ<br><br>
−$N+\Delta=m(\frac{gR\varphi^2}{R}+g)=mg(1+\varphi^2)=mg(1+\frac{A^2}{R^2})$ (2)<br><br>
+$N=mgcos\varphi\approx mg(1-\frac{\varphi^2}{2})$$=mg(1-\frac{A^2}{2R^2})$ (1)<br><br>
+$N+\Delta$$=m(a+g)$$=m(\frac{\upsilon^2}{R}+g)$<br><br>
+$mgR(1-cos\varphi)\approx mgR\frac{\varphi^2}{2}$$=\frac{m\upsilon^2}{2}$ - ЗСЭ<br><br>
+$N+\Delta=m(\frac{gR\varphi^2}{R}+g)$$=mg(1+\varphi^2)$$=mg(1+\frac{A^2}{R^2})$ (2)<br><br>
Далее решаем систему из уравнений (1) и (2) и получаем, что: <br><br>
$\fbox{$A=R\sqrt{\frac{2\Delta}{3N+\Delta}}$}$<br><br>
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