Added alternative solution to 3.2.3 3.2.4 3.2.6 3.2.7 3.2.8 3.2.9 3.2.10 3.2.11 3.2.12 3.2.13 3.2.14 3.2.18 3.2.19 3.2.20 3.2.21 3.2.22 3.2.23 3.2.24 3.2.25 3.2.28 3.2.29 3.2.31

astrosander edited
revision #417 parent #371 GitHub fbdf260 ← older newer →
@@ -180,6 +180,14 @@
$ma=\frac{\mu mg(l+x)}{l}-\frac{\mu mg(l-x)}{l}$$=\frac{\mu mg(l+x-l+x)}{l}$$=\frac{2\mu mgx}{l}$<br><br>
$\ddot{x}(t)+\frac{2\mu g}{l}x(t)=0$<br><br>
$\omega=\sqrt{\frac{2\mu g}{l}}$<br><br>
+
+ <hr>
+ <h3>
+ Альтернативное решение:
+ </h3>
+ <div class="solutions">
+ <img class="ScreenS" src="01.jpg">
+ </div>
<h3>
Ответ: $\omega=\sqrt{\frac{2\mu g}{l}}$.
<h3>
unchanged lines 55