Added 7.1.12, 7.1.23, 7.3.9 & 11.5.11
en/7.1.23.md
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| + | <meta name="author" content="Aliaksandr Melnichenka"> | ||
| + | <meta name="date" content="2023-10" scheme="YYYY-MM"> | ||
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| + | <title>Find the period of small vibrations of a body of mass m, whose charge is q, inside a smooth sphere of radius R, if the charge Q is fixed at the top point of the sphere.</title> | ||
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| + | <a href="../../" style="text-decoration: none;"> | ||
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| + | <span><img src="../../img/book.png"></span><span>Savchenko Solutions</span> | ||
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| + | </a> | ||
| + | <p class="author"> | ||
| + | Solutions of Savchenko Problems in Physics <br> | ||
| + | <i><b>knowledge must be free</b></i> | ||
| + | </p> | ||
| + | </header> | ||
| + | |||
| + | <h3 id="back-link"><a href="../../#7.1">$\leftarrow$Back</a></h3> | ||
| + | |||
| + | <h3> Statement </h3> | ||
| + | <p> | ||
| + | $7.1.23^*.$ Find the period of small vibrations of a body of mass $m$, whose charge is $q$, inside a smooth sphere of radius $R$, if the charge $Q$ is fixed at the top point of the sphere. | ||
| + | </p> | ||
| + | <center> | ||
| + | <figure> | ||
| + | <img src="7.1.23.png" | ||
| + | loading="lazy" width="200" /> | ||
| + | <figcaption> | ||
| + | For problem $7.1.23^*$ | ||
| + | </figcaption> | ||
| + | </figure> | ||
| + | </center> | ||
| + | <p> | ||
| + | </p> | ||
| + | |||
| + | <h3>Solution</h3> | ||
| + | <p> | ||
| + | |||
| + | </p> | ||
| + | <center> | ||
| + | <figure> | ||
| + | <img src="7.1.23_1.png" | ||
| + | loading="lazy" width="200" /> | ||
| + | <figcaption> | ||
| + | Forces acting on the system of two charges | ||
| + | </figcaption> | ||
| + | </figure> | ||
| + | </center> | ||
| + | <p> | ||
| + | |||
| + | Considering the fact that oscillations are small, $\varphi \ll 1$, we could use the approximations for small angle $\varphi$ | ||
| + | $$\sin\varphi \approx \varphi; \quad\cos\varphi \approx 1\quad(1)$$ | ||
| + | From where, we could approximate that the distance between charges remains approximately the same | ||
| + | $$r\approx2R$$ | ||
| + | Thus, the сoulomb's law for two charges | ||
| + | $$F_c = \frac{1}{4\pi\varepsilon_0}\frac{qQ}{4R^2}$$ | ||
| + | Let's write Newton's second law on a tangential trajectory, in the direction of motion of a charge of mass $m$ | ||
| + | $$ma = mg \sin\varphi + F_c \sin\frac{\varphi}{2}$$ | ||
| + | Considering the approximation $(1)$ and the expression | ||
| + | $$ma = -mg\frac{x}{R} - \frac{x}{2R} \frac{1}{4\pi\varepsilon_0}\frac{qQ}{4R^2}$$ | ||
| + | $$a = -x\left(\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}\right)$$ | ||
| + | Solving the equation of harmonic oscillations $(\ddot{x}+\omega^2x(t)=0)$, we could obtain the value for angular velocity | ||
| + | $$\omega=\sqrt{\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}}$$ | ||
| + | From here the period of oscillation | ||
| + | $$\boxed{T=\frac{2\pi}{\omega} = \frac{2\pi}{\sqrt{\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}}}}$$ | ||
| + | Since the expression under the square root cannot be less than zero, the ratio at which there will be no oscillations | ||
| + | $$\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3} > 0 \Leftrightarrow \boxed{\frac{qQ}{32\pi\varepsilon_0R^2}>-mg}$$ | ||
| + | </p> | ||
| + | |||
| + | <h4>Answer</h4> | ||
| + | <div class="scroll-wrapper"> | ||
| + | <p> | ||
| + | $$T=2\pi\left(\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}\right)^{-1/2}\text{ with }\frac{qQ}{32\pi\varepsilon_0R^2}>-mg$$ | ||
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| <html lang="en"> | |||
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| <meta charset="utf-8"> | |||
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| <meta name="description" content="Find the period of small vibrations of a body of mass m, whose charge is q, inside a smooth sphere of radius R, if the charge Q is fixed at the top point of the sphere."> | |||
| <meta name="author" content="Aliaksandr Melnichenka"> | |||
| <meta name="date" content="2023-10" scheme="YYYY-MM"> | |||
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| <a href="../../" style="text-decoration: none;"> | |||
| <div id="logo"> | |||
| <span><img src="../../img/book.png"></span><span>Savchenko Solutions</span> | |||
| </div> | |||
| </a> | |||
| <p class="author"> | |||
| Solutions of Savchenko Problems in Physics <br> | |||
| <i><b>knowledge must be free</b></i> | |||
| </p> | |||
| </header> | |||
| <h3 id="back-link"><a href="../../#7.1">$\leftarrow$Back</a></h3> | |||
| <h3> Statement </h3> | |||
| <p> | |||
| $7.1.23^*.$ Find the period of small vibrations of a body of mass $m$, whose charge is $q$, inside a smooth sphere of radius $R$, if the charge $Q$ is fixed at the top point of the sphere. | |||
| </p> | |||
| <center> | |||
| <figure> | |||
| <img src="7.1.23.png" | |||
| loading="lazy" width="200" /> | |||
| <figcaption> | |||
| For problem $7.1.23^*$ | |||
| </figcaption> | |||
| </figure> | |||
| </center> | |||
| <p> | |||
| </p> | |||
| <h3>Solution</h3> | |||
| <p> | |||
| </p> | |||
| <center> | |||
| <figure> | |||
| <img src="7.1.23_1.png" | |||
| loading="lazy" width="200" /> | |||
| <figcaption> | |||
| Forces acting on the system of two charges | |||
| </figcaption> | |||
| </figure> | |||
| </center> | |||
| <p> | |||
| Considering the fact that oscillations are small, $\varphi \ll 1$, we could use the approximations for small angle $\varphi$ | |||
| $$\sin\varphi \approx \varphi; \quad\cos\varphi \approx 1\quad(1)$$ | |||
| From where, we could approximate that the distance between charges remains approximately the same | |||
| $$r\approx2R$$ | |||
| Thus, the сoulomb's law for two charges | |||
| $$F_c = \frac{1}{4\pi\varepsilon_0}\frac{qQ}{4R^2}$$ | |||
| Let's write Newton's second law on a tangential trajectory, in the direction of motion of a charge of mass $m$ | |||
| $$ma = mg \sin\varphi + F_c \sin\frac{\varphi}{2}$$ | |||
| Considering the approximation $(1)$ and the expression | |||
| $$ma = -mg\frac{x}{R} - \frac{x}{2R} \frac{1}{4\pi\varepsilon_0}\frac{qQ}{4R^2}$$ | |||
| $$a = -x\left(\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}\right)$$ | |||
| Solving the equation of harmonic oscillations $(\ddot{x}+\omega^2x(t)=0)$, we could obtain the value for angular velocity | |||
| $$\omega=\sqrt{\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}}$$ | |||
| From here the period of oscillation | |||
| $$\boxed{T=\frac{2\pi}{\omega} = \frac{2\pi}{\sqrt{\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}}}}$$ | |||
| Since the expression under the square root cannot be less than zero, the ratio at which there will be no oscillations | |||
| $$\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3} > 0 \Leftrightarrow \boxed{\frac{qQ}{32\pi\varepsilon_0R^2}>-mg}$$ | |||
| </p> | |||
| <h4>Answer</h4> | |||
| <div class="scroll-wrapper"> | |||
| <p> | |||
| $$T=2\pi\left(\frac{g}{R}+\frac{qQ}{32\pi\varepsilon_0mR^3}\right)^{-1/2}\text{ with }\frac{qQ}{32\pi\varepsilon_0R^2}>-mg$$ | |||
| </p> | |||
| </div> | |||
| <footer class="row container"> | |||
| <br> | |||
| <p> | |||
| <small> © <strong>Savchenko Solutions</strong>, 2023-2024 <br></small> | |||
| </p> | |||
| <p> | |||
| <small>All rights belong to the authors. <br> Commercial use of materials - with the written permission of the authors. <br> alex@savchenkosolutions.com <br></small> | |||
| </p> | |||
| </footer> | |||
| </body> | |||
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